EDIT: I feel I must admit, as pointed out by a few others—who never left me comments—that the previous version of my answer (which you accepted) had a bug that prevented it from properly handling column numbers greater than 702
(corresponding to Excel column 'ZZ'
). So, in the interests of correctness, that's been fixed in the code below, which now contains a loop just like many of the other answers do.
It's quite likely you never used the previous version with large enough column numbers to have encountered the issue. FWIW, the MS specs for the current version of Excel say it supports worksheets with up to 16,384 columns (Excel column 'XFD'
).
LETTERS = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
def excel_style(row, col):
""" Convert given row and column number to an Excel-style cell name. """
result = []
while col:
col, rem = divmod(col-1, 26)
result[:0] = LETTERS[rem]
return ''.join(result) + str(row)
if __name__ == '__main__':
addresses = [(1, 1), (1, 26),
(1, 27), (1, 52),
(1, 53), (1, 78),
(1, 79), (1, 104),
(1, 18253), (1, 18278),
(1, 702), # -> 'ZZ1'
(1, 703), # -> 'AAA1'
(1, 16384), # -> 'XFD1'
(1, 35277039)]
print('({:3}, {:>10}) --> {}'.format('row', 'col', 'Excel'))
print('==========================')
for row, col in addresses:
print('({:3}, {:10,}) --> {!r}'.format(row, col, excel_style(row, col)))
Output:
(row, col) --> Excel
========================
( 1, 1) --> 'A1'
( 1, 26) --> 'Z1'
( 1, 27) --> 'AA1'
( 1, 52) --> 'AZ1'
( 1, 53) --> 'BA1'
( 1, 78) --> 'BZ1'
( 1, 79) --> 'CA1'
( 1, 104) --> 'CZ1'
( 1, 18253) --> 'ZZA1'
( 1, 18278) --> 'ZZZ1'
( 1, 702) --> 'ZZ1'
( 1, 703) --> 'AAA1'
( 1, 16384) --> 'XFD1'
( 1, 35277039) --> 'BYEBYE1'