I know you were not asking about the VBA, but it maybe you will give it a chance
If you open a VBA project, insert new module, then pick Tools -> References and add a reference to Microsoft VBScript Regular Expressions 5.5. Given that pate the code below to the newly inserted module.
Function my_regexp(ByRef sIn As String, ByVal mypattern As String) As String
Dim r As New RegExp
Dim colMatches As MatchCollection
With r
.Pattern = mypattern
.IgnoreCase = True
.Global = False
.MultiLine = False
Set colMatches = .Execute(sIn)
End With
If colMatches.Count > 0 Then
my_regexp = colMatches(0).Value
Else
my_regexp = ""
End If
End Function
Now you may use the function above in your SQL queries. So your question would be now solved by invoking
SELECT my_regexp(some_variable, "^[0]{1}[0-9]{8,9}$") FROM some_table
if will return empty string if nothing is matched.
Hope you liked it.
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