Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
499 views
in Technique[技术] by (71.8m points)

regex - Why do ^ and $ not work as expected?

This puzzled me the last 15 minutes:

if ('ab' =~ /^a|b$/) { print 't' } else { print 'f' }
print "
";

I have expected that 'a' or 'b' following the beginning and followed by the end, should match only one character. So the test should fail for two characters 'ab'. But it succeeds. Why?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

If you group the alternation, then you will get the expected behavior:

/^(a|b)$/

Your regex will find a a at the start of the string (with ^a branch) or b at the end (with the b$ branch).

When you use ^(a|b)$, the anchors are applied to the whole group and thus it will match a string that is equal to a or b.

Also, if you do not really need to capture the value, you may either use a non-capturing group, /^(?:a|b)$/, or a n modifier, /^(a|b)$/n.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...