swift - Swipe-able Table View Cell in iOS 9

Question

I want my table list to have a swipe-able menu like in iOS 8 (first introduced in iOS 7).

I've found a Ray Wenderlich guide that is clear on how to do it, but it was written a year and 4 months ago and the code is in Objective-C.

Did iOS 8 or the upcoming iOS 9 finally include this function in Apple's SDK? I know they made the "swipe to reveal delete function" built-in years ago. I don't want to waste my time implementing patched-together code to mimic the iOS 8 mail function, if Apple's new iOS is going to hand it to me in a neatly wrapped package.

Answer 1

Try this, updated for Swift 3 (Developer Docs)

override func tableView(_ tableView: UITableView, editActionsForRowAt: IndexPath) -> [UITableViewRowAction]? {
    let more = UITableViewRowAction(style: .normal, title: "More") { action, index in
        print("more button tapped")
    }
    more.backgroundColor = .lightGray
    
    let favorite = UITableViewRowAction(style: .normal, title: "Favorite") { action, index in
        print("favorite button tapped")
    }
    favorite.backgroundColor = .orange
    
    let share = UITableViewRowAction(style: .normal, title: "Share") { action, index in
        print("share button tapped")
    }
    share.backgroundColor = .blue
    
    return [share, favorite, more]
}

Also implement this: (You can make it conditional, but here everything is editable)

override func tableView(_ tableView: UITableView, canEditRowAt indexPath: IndexPath) -> Bool {
    return true
}