GCC is correct and the other compiler is correct too. Refer to 14.6p8 in the spec
If no valid specialization can be generated for a template definition, and that template is not instantiated, the template de?nition is ill-formed, no diagnostic required.
Therefor, a compiler is free to reject the following
template<typename T>
void f() {
static_assert(0, "may trigger immediately!");
static_assert(sizeof(T) == 0, "may trigger immediately!");
}
If you want to go safe, you have to arrange it so the compiler cannot know until instantiation whether the boolean expression will be true or false. For example, get the value by getvalue<T>::value
, with getvalue
being a class template (one could specialize it, so the compiler cannot possibly know the boolean value already).
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