I have the following generic method for serialising an input object of one type as a super-type as follows:
public string SerialiseAs<TResult, TInput>(TInput input) where TInput : TResult
{
DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(TResult));
MemoryStream stream = new MemoryStream();
ser.WriteObject(stream, input);
stream.Position = 0;
StreamReader reader = new StreamReader(stream);
return reader.ReadToEnd();
}
I have to call this method specifying both generic types as follows:
MySubType x = new MySubType();
string json = SerialiseAs<MySuperType, MySubType>(x);
My question is, why can't TInput
be inferred in this situation? Is it because TResult
isn't actually used as the return type? The following code is cleaner but won't compile because of the missing input type:
MySubType x = new MySubType();
string json = SerialiseAs<MySuperType>(x);
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…