Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
888 views
in Technique[技术] by (71.8m points)

bash - Padding characters in printf

I am writing a bash shell script to display if a process is running or not.

So far, I got this:

printf "%-50s %s
" $PROC_NAME [UP]

The code gives me this output:

JBoss                                              [DOWN]

GlassFish                                          [UP]

verylongprocessname                                [UP]

I want to pad the gap between the two fields with a '-' or '*' to make it more readable. How do I do that without disturbing the alignment of the fields?

The output I want is:

JBoss -------------------------------------------  [DOWN]

GlassFish ---------------------------------------  [UP]

verylongprocessname -----------------------------  [UP]
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Pure Bash, no external utilities

This demonstration does full justification, but you can just omit subtracting the length of the second string if you want ragged-right lines.

pad=$(printf '%0.1s' "-"{1..60})
padlength=40
string2='bbbbbbb'
for string1 in a aa aaaa aaaaaaaa
do
     printf '%s' "$string1"
     printf '%*.*s' 0 $((padlength - ${#string1} - ${#string2} )) "$pad"
     printf '%s
' "$string2"
     string2=${string2:1}
done

Unfortunately, in that technique, the length of the pad string has to be hardcoded to be longer than the longest one you think you'll need, but the padlength can be a variable as shown. However, you can replace the first line with these three to be able to use a variable for the length of the pad:

padlimit=60
pad=$(printf '%*s' "$padlimit")
pad=${pad// /-}

So the pad (padlimit and padlength) could be based on terminal width ($COLUMNS) or computed from the length of the longest data string.

Output:

a--------------------------------bbbbbbb
aa--------------------------------bbbbbb
aaaa-------------------------------bbbbb
aaaaaaaa----------------------------bbbb

Without subtracting the length of the second string:

a---------------------------------------bbbbbbb
aa--------------------------------------bbbbbb
aaaa------------------------------------bbbbb
aaaaaaaa--------------------------------bbbb

The first line could instead be the equivalent (similar to sprintf):

printf -v pad '%0.1s' "-"{1..60}

or similarly for the more dynamic technique:

printf -v pad '%*s' "$padlimit"

You can do the printing all on one line if you prefer:

printf '%s%*.*s%s
' "$string1" 0 $((padlength - ${#string1} - ${#string2} )) "$pad" "$string2"

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...