I'm not sure I fully understand the question but I'll attempt to answer by providing a few details about profiles in Spring Boot.
For your #1 example, according to the docs you can select the profile using the Spring Boot Maven plugin using -Drun.profiles
.
Edit: For Spring Boot 2.0+ run
has been renamed to spring-boot.run
and run.profiles
has been renamed to spring-boot.run.profiles
mvn spring-boot:run -Dspring-boot.run.profiles=dev
https://docs.spring.io/spring-boot/docs/2.0.1.RELEASE/maven-plugin/examples/run-profiles.html
From your #2 example, you are defining the active profile after the name of the jar. You need to provide the JVM argument before the name of the jar you are running.
java -jar -Dspring.profiles.active=dev XXX.jar
General info:
You mention that you have both an application.yml
and a application-dev.yml
. Running with the dev
profile will actually load both config files. Values from application-dev.yml
will override the same values provided by application.yml
but values from both yml
files will be loaded.
There are also multiple ways to define the active profile.
You can define them as you did, using -Dspring.profiles.active
when running your jar. You can also set the profile using a SPRING_PROFILES_ACTIVE
environment variable or a spring.profiles.active
system property.
More info can be found here:
https://docs.spring.io/spring-boot/docs/current/reference/html/howto.html#howto-set-active-spring-profiles
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