Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
694 views
in Technique[技术] by (71.8m points)

python - How to display progress of scipy.optimize function?

I use scipy.optimize to minimize a function of 12 arguments.

I started the optimization a while ago and still waiting for results.

Is there a way to force scipy.optimize to display its progress (like how much is already done, what are the current best point)?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

As mg007 suggested, some of the scipy.optimize routines allow for a callback function (unfortunately leastsq does not permit this at the moment). Below is an example using the "fmin_bfgs" routine where I use a callback function to display the current value of the arguments and the value of the objective function at each iteration.

import numpy as np
from scipy.optimize import fmin_bfgs

Nfeval = 1

def rosen(X): #Rosenbrock function
    return (1.0 - X[0])**2 + 100.0 * (X[1] - X[0]**2)**2 + 
           (1.0 - X[1])**2 + 100.0 * (X[2] - X[1]**2)**2

def callbackF(Xi):
    global Nfeval
    print '{0:4d}   {1: 3.6f}   {2: 3.6f}   {3: 3.6f}   {4: 3.6f}'.format(Nfeval, Xi[0], Xi[1], Xi[2], rosen(Xi))
    Nfeval += 1

print  '{0:4s}   {1:9s}   {2:9s}   {3:9s}   {4:9s}'.format('Iter', ' X1', ' X2', ' X3', 'f(X)')   
x0 = np.array([1.1, 1.1, 1.1], dtype=np.double)
[xopt, fopt, gopt, Bopt, func_calls, grad_calls, warnflg] = 
    fmin_bfgs(rosen, 
              x0, 
              callback=callbackF, 
              maxiter=2000, 
              full_output=True, 
              retall=False)

The output looks like this:

Iter    X1          X2          X3         f(X)      
   1    1.031582    1.062553    1.130971    0.005550
   2    1.031100    1.063194    1.130732    0.004973
   3    1.027805    1.055917    1.114717    0.003927
   4    1.020343    1.040319    1.081299    0.002193
   5    1.005098    1.009236    1.016252    0.000739
   6    1.004867    1.009274    1.017836    0.000197
   7    1.001201    1.002372    1.004708    0.000007
   8    1.000124    1.000249    1.000483    0.000000
   9    0.999999    0.999999    0.999998    0.000000
  10    0.999997    0.999995    0.999989    0.000000
  11    0.999997    0.999995    0.999989    0.000000
Optimization terminated successfully.
         Current function value: 0.000000
         Iterations: 11
         Function evaluations: 85
         Gradient evaluations: 17

At least this way you can watch as the optimizer tracks the minimum


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...