You can invoke a PHP script manually from the command line
hello.php
<?php
echo 'hello world!';
?>
Command line:
php hello.php
Output:
hello world!
See the documentation: http://php.net/manual/en/features.commandline.php
EDIT OP edited the question to add a critical detail: the script is to be executed by another script.
There are a couple of approaches. First and easiest, you could simply include the file. When you include a file, the code within is "executed" (actually, interpreted). Any code that is not within a function or class body will be processed immediately. Take a look at the documentation for include (docs) and/or require (docs) (note: include_once and require_once are related, but different in an important way. Check out the documents to understand the difference) Your code would look like this:
include('hello.php');
/* output
hello world!
*/
Second and slightly more complex is to use shell_exec (docs). With shell_exec, you will call the php binary and pass the desired script as the argument. Your code would look like this:
$output = shell_exec('php hello.php');
echo "<pre>$output</pre>";
/* output
hello world!
*/
Finally, and most complex, you could use the CURL library to call the file as though it were requested via a browser. Check out the CURL library documentation here: http://us2.php.net/manual/en/ref.curl.php
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://www.myDomain.com/hello.php");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true)
$output = curl_exec($ch);
curl_close($ch);
echo "<pre>$output</pre>";
/* output
hello world!
*/
Documentation for functions used
与恶龙缠斗过久,自身亦成为恶龙；凝视深渊过久,深渊将回以凝视…
