What is the difference between & and && operators in C#

Question

I am trying to understand the difference between & and &&operators in C#. I searched on the internet without success. Can somebody please explain with an example?

Answer 1

& is the bitwise AND operator. For operands of integer types, it'll calculate the bitwise-AND of the operands and the result will be an integer type. For boolean operands, it'll compute the logical-and of operands. && is the logical AND operator and doesn't work on integer types. For boolean types, where both of them can be applied, the difference is in the "short-circuiting" property of &&. If the first operand of && evaluates to false, the second is not evaluated at all. This is not the case for &:

 bool f() {
    Console.WriteLine("f called");
    return false;
 }
 bool g() {
    Console.WriteLine("g called");
    return false;
 }
 static void Main() {
    bool result = f() && g(); // prints "f called"
    Console.WriteLine("------");
    result = f() & g(); // prints "f called" and "g called"
 }

|| is similar to && in this property; it'll only evaluate the second operand if the first evaluates to false.

Of course, user defined types can overload these operators making them do anything they want.