Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
470 views
in Technique[技术] by (71.8m points)

python - Filling in date gaps in MultiIndex Pandas Dataframe

I would like to modify a pandas MultiIndex DataFrame such that each index group includes Dates between a specified range. I would like each group to fill in missing dates 2013-06-11 to 2013-12-31 with the value 0 (or NaN).

Group A, Group B, Date,           Value
loc_a    group_a  2013-06-11      22
                  2013-07-02      35
                  2013-07-09      14
                  2013-07-30       9
                  2013-08-06       4
                  2013-09-03      40
                  2013-10-01      18
         group_b  2013-07-09       4
                  2013-08-06       2
                  2013-09-03       5
         group_c  2013-07-09       1
                  2013-09-03       2
loc_b    group_a  2013-10-01       3

I've seen a few discussions of reindexing, but that is for a simple (non-grouped) time-series data.

Is there an easy way to do this?


Following are some attempts I've made at accomplishing this. For example: Once I've unstacked by ['A', 'B'], I can then reindex.

df = pd.DataFrame({'A': ['loc_a'] * 12 + ['loc_b'],
                'B': ['group_a'] * 7 + ['group_b'] * 3 + ['group_c'] * 2 + ['group_a'],
                'Date': ["2013-06-11",
                        "2013-07-02",
                        "2013-07-09",
                        "2013-07-30",
                        "2013-08-06",
                        "2013-09-03",
                        "2013-10-01",
                        "2013-07-09",
                        "2013-08-06",
                        "2013-09-03",
                        "2013-07-09",
                        "2013-09-03",
                        "2013-10-01"],
                 'Value': [22, 35, 14,  9,  4, 40, 18, 4, 2, 5, 1, 2, 3]})

df.Date = df['Date'].apply(lambda x: pd.to_datetime(x).date())
df = df.set_index(['A', 'B', 'Date'])

dt_start = dt.datetime(2013,6,1)
all_dates = [(dt_start + dt.timedelta(days=x)).date() for x in range(0,60)]

df2 = df.unstack(['A', 'B'])
df3 = df2.reindex(index=all_dates).fillna(0)
df4 = df3.stack(['A', 'B'])

## df4 is about where I want to get, now I'm trying to get it back in the form of df...

df5 = df4.reset_index()
df6 = df5.rename(columns={'level_0' : 'Date'})
df7 = df6.groupby(['A', 'B', 'Date'])['Value'].sum()

The last few lines make me a little sad. I was hoping that at df6 I could simply set_index back to ['A', 'B', 'Date'], but that did not group the values as they are grouped in the initial df DataFrame.

Any thoughts on how I can reindex the unstacked DataFrame, restack, and have the DataFrame in the same format as the original?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can make a new multi index based on the Cartesian product of the levels of the existing multi index. Then, re-index your data frame using the new index.

new_index = pd.MultiIndex.from_product(df.index.levels)
new_df = df.reindex(new_index)

# Optional: convert missing values to zero, and convert the data back
# to integers. See explanation below.
new_df = new_df.fillna(0).astype(int)

That's it! The new data frame has all the possible index values. The existing data is indexed correctly.

Read on for a more detailed explanation.


Explanation

Set up sample data

import pandas as pd

df = pd.DataFrame({'A': ['loc_a'] * 12 + ['loc_b'],
                   'B': ['group_a'] * 7 + ['group_b'] * 3 + ['group_c'] * 2 + ['group_a'],
                   'Date': ["2013-06-11",
                           "2013-07-02",
                           "2013-07-09",
                           "2013-07-30",
                           "2013-08-06",
                           "2013-09-03",
                           "2013-10-01",
                           "2013-07-09",
                           "2013-08-06",
                           "2013-09-03",
                           "2013-07-09",
                           "2013-09-03",
                           "2013-10-01"],
                    'Value': [22, 35, 14,  9,  4, 40, 18, 4, 2, 5, 1, 2, 3]})

df.Date = pd.to_datetime(df.Date)

df = df.set_index(['A', 'B', 'Date'])

Here's what the sample data looks like

                          Value
A     B       Date
loc_a group_a 2013-06-11     22
              2013-07-02     35
              2013-07-09     14
              2013-07-30      9
              2013-08-06      4
              2013-09-03     40
              2013-10-01     18
      group_b 2013-07-09      4
              2013-08-06      2
              2013-09-03      5
      group_c 2013-07-09      1
              2013-09-03      2
loc_b group_a 2013-10-01      3

Make new index

Using from_product we can make a new multi index. This new index is the Cartesian product of all the values from all the levels of the old index.

new_index = pd.MultiIndex.from_product(df.index.levels)

Reindex

Use the new index to reindex the existing data frame.

new_df = df.reindex(new_index)

All the possible combinations are now present. The missing values are null (NaN).

The expanded, re-indexed data frame looks like this:

                          Value
loc_a group_a 2013-06-11   22.0
              2013-07-02   35.0
              2013-07-09   14.0
              2013-07-30    9.0
              2013-08-06    4.0
              2013-09-03   40.0
              2013-10-01   18.0
      group_b 2013-06-11    NaN
              2013-07-02    NaN
              2013-07-09    4.0
              2013-07-30    NaN
              2013-08-06    2.0
              2013-09-03    5.0
              2013-10-01    NaN
      group_c 2013-06-11    NaN
              2013-07-02    NaN
              2013-07-09    1.0
              2013-07-30    NaN
              2013-08-06    NaN
              2013-09-03    2.0
              2013-10-01    NaN
loc_b group_a 2013-06-11    NaN
              2013-07-02    NaN
              2013-07-09    NaN
              2013-07-30    NaN
              2013-08-06    NaN
              2013-09-03    NaN
              2013-10-01    3.0
      group_b 2013-06-11    NaN
              2013-07-02    NaN
              2013-07-09    NaN
              2013-07-30    NaN
              2013-08-06    NaN
              2013-09-03    NaN
              2013-10-01    NaN
      group_c 2013-06-11    NaN
              2013-07-02    NaN
              2013-07-09    NaN
              2013-07-30    NaN
              2013-08-06    NaN
              2013-09-03    NaN
              2013-10-01    NaN

Nulls in integer column

You can see that the data in the new data frame has been converted from ints to floats. Pandas can't have nulls in an integer column. Optionally, we can convert all the nulls to 0, and cast the data back to integers.

new_df = new_df.fillna(0).astype(int)

Result

                          Value
loc_a group_a 2013-06-11     22
              2013-07-02     35
              2013-07-09     14
              2013-07-30      9
              2013-08-06      4
              2013-09-03     40
              2013-10-01     18
      group_b 2013-06-11      0
              2013-07-02      0
              2013-07-09      4
              2013-07-30      0
              2013-08-06      2
              2013-09-03      5
              2013-10-01      0
      group_c 2013-06-11      0
              2013-07-02      0
              2013-07-09      1
              2013-07-30      0
              2013-08-06      0
              2013-09-03      2
              2013-10-01      0
loc_b group_a 2013-06-11      0
              2013-07-02      0
              2013-07-09      0
              2013-07-30      0
              2013-08-06      0
              2013-09-03      0
              2013-10-01      3
      group_b 2013-06-11      0
              2013-07-02      0
              2013-07-09      0
              2013-07-30      0
              2013-08-06      0
              2013-09-03      0
              2013-10-01      0
      group_c 2013-06-11      0
              2013-07-02      0
              2013-07-09      0
              2013-07-30      0
              2013-08-06      0
              2013-09-03      0
              2013-10-01      0

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...