I am trying to extract the bits from a float without invoking undefined behavior. Here is my first attempt:
unsigned foo(float x)
{
unsigned* u = (unsigned*)&x;
return *u;
}
As I understand it, this is not guaranteed to work due to strict aliasing rules, right? Does it work if a take an intermediate step with a character pointer?
unsigned bar(float x)
{
char* c = (char*)&x;
unsigned* u = (unsigned*)c;
return *u;
}
Or do I have to extract the individual bytes myself?
unsigned baz(float x)
{
unsigned char* c = (unsigned char*)&x;
return c[0] | c[1] << 8 | c[2] << 16 | c[3] << 24;
}
Of course this has the disadvantage of depending on endianness, but I could live with that.
The union hack is definitely undefined behavior, right?
unsigned uni(float x)
{
union { float f; unsigned u; };
f = x;
return u;
}
Just for completeness, here is a reference version of foo
. Also undefined behavior, right?
unsigned ref(float x)
{
return (unsigned&)x;
}
So, is it possible to extract the bits from a float (assuming both are 32 bits wide, of course)?
EDIT: And here is the memcpy
version as proposed by Goz. Since many compilers do not support static_assert
yet, I have replaced static_assert
with some template metaprogramming:
template <bool, typename T>
struct requirement;
template <typename T>
struct requirement<true, T>
{
typedef T type;
};
unsigned bits(float x)
{
requirement<sizeof(unsigned)==sizeof(float), unsigned>::type u;
memcpy(&u, &x, sizeof u);
return u;
}
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