Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
700 views
in Technique[技术] by (71.8m points)

networking - API for configuring static IP addresses in an Android application

Is it possible to set the IP address of an interface in Android within an application?

I can query the available interfaces and their current addresses using java.net.NetworkInterface, but this doesn't provide a facility to change these. Did I just miss something somewhere, or is it not allowed?

I was hoping to be able to make my application either change or add an alias to one or more of the existing interfaces at runtime on an "off the shelf" device. (2.1/2.2). Ideally I'd like to do this for both IPv4 and IPv6 addresses.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Settings.System includes several flags you can use for this:

  • WIFI_USE_STATIC_IP
  • WIFI_STATIC_IP
  • WIFI_STATIC_NETMASK
  • WIFI_STATIC_GATEWAY
  • WIFI_STATIC_DNS1 and WIFI_STATIC_DNS2

You'll also need the android.permission.WRITE_SETTINGS permission declared for your application.

Then in your activity:

final ContentResolver cr = getContentResolver();
Settings.System.putInt(cr, Settings.System.WIFI_USE_STATIC_IP, 1);
Settings.System.putString(cr, Settings.System.WIFI_STATIC_IP, "you.re.ip.addr");
// call putString() for each value to set for your interface

If you want to change the IP address of the carrier's 3G/4G,etc interface, I do not believe this is possible - as it is connected to the carrier and uses their DHCP/security for enabling you to connect and use their services (sort of like changing the external IP of your cable modem without the consent of your ISP).


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...