Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
614 views
in Technique[技术] by (71.8m points)

c - How does the compare function in qsort work?

I found this sample code online, which explains how the qsort function works. I could not understand what the compare function returns.

#include "stdlib.h"

int values[] = { 88, 56, 100, 2, 25 };

int cmpfunc (const void * a, const void * b) //what is it returning?
{
   return ( *(int*)a - *(int*)b ); //What is a and b?
}


int main(int argc, _TCHAR* argv[])
{

   int n;

   printf("Before sorting the list is: 
");
   for( n = 0 ; n < 5; n++ ) {
      printf("%d ", values[n]);
   }

   qsort(values, 5, sizeof(int), cmpfunc);

   printf("
After sorting the list is: 
");
   for( n = 0 ; n < 5; n++ ) {
      printf("%d ", values[n]);
   }
    return 0;
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

What a and b are is clearly stated in the documentation for qsort: these are pointers that point to array elements that have to be compared.

Comparison function in this case knows that the array elements are of type int. So it casts the void * pointers to int * type and performs a tri-state comparison of the pointed int values by subtracting the second from the first.

It will work properly for your set of values, but in general case using subtraction for tri-state comparison is a bad programming practice, since it is prone to overflow. Also, the function in your sample code unnecessarily casts away the constness of the pointed values.

A better alternative would be

int cmpfunc(const void *a, const void *b)
{
   const int *A = a, *B = b;
   return (*A > *B) - (*A < *B);
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...