escaping - How to echo a variable containing an unescaped dollar sign in bash

Question

If I have a variable containing an unescaped dollar sign, is there any way I can echo the entire contents of the variable?

For example something calls a script:

./script.sh "test1$test2"

and then if I want to use the parameter it gets "truncated" like so:

echo ${1}
test1

Of course single-quoting the varaible name doesn't help. I can't figure out how to quote it so that I can at least escape the dollar sign myself once the script recieves the parameter.

Answer 1

The problem is that script receives "test1" in the first place and it cannot possibly know that there was a reference to an empty (undeclared) variable. You have to escape the $ before passing it to the script, like this:

./script.sh "test1$test2"

Or use single quotes ' like this:

./script.sh 'test1$test2'

In which case bash will not expand variables from that parameter string.