To make sure you're sampling uniformly, you could just generate all the permutations and limit to those that sum to 7:
library(gtools)
perms <- permutations(8, 7, 0:7, repeats.allowed=T)
perms7 <- perms[rowSums(perms) == 7,]
From nrow(perms7)
, we see there are only 1716 possible permutations that sum to 7. Now you can uniformly sample from the permutations:
set.seed(144)
my.perms <- perms7[sample(nrow(perms7), 100000, replace=T),]
head(my.perms)
# [,1] [,2] [,3] [,4] [,5] [,6] [,7]
# [1,] 0 0 0 2 5 0 0
# [2,] 1 3 0 1 2 0 0
# [3,] 1 4 1 1 0 0 0
# [4,] 1 0 0 3 0 3 0
# [5,] 0 2 0 0 0 5 0
# [6,] 1 1 2 0 0 2 1
An advantage of this approach is that it's easy to see that we're sampling uniformly at random. Also, it's quite quick -- building perms7
took 0.3 seconds on my computer and building a 1 million-row my.perms
took 0.04 seconds. If you need to draw many vectors this will be quite a bit quicker than a recursive approach because you're just using matrix indexing into perms7
instead of generating each vector separately.
Here's a distribution of counts of numbers in the sample:
# 0 1 2 3 4 5 6 7
# 323347 188162 102812 51344 22811 8629 2472 423
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