Create a new helper (ex. app/helpers/will_paginate_helper.rb) with the following content:
module WillPaginateHelper
class WillPaginateJSLinkRenderer < WillPaginate::ActionView::LinkRenderer
def prepare(collection, options, template)
options[:params] ||= {}
options[:params]['_'] = nil
super(collection, options, template)
end
protected
def link(text, target, attributes = {})
if target.is_a? Fixnum
attributes[:rel] = rel_value(target)
target = url(target)
end
@template.link_to(target, attributes.merge(remote: true)) do
text.to_s.html_safe
end
end
end
def js_will_paginate(collection, options = {})
will_paginate(collection, options.merge(:renderer => WillPaginateHelper::WillPaginateJSLinkRenderer))
end
end
Then in your view use this tag for ajax pagination:
<%= js_will_paginate @recipes %>
Remember that the pagination links will include existing params of the url, you can exclude these as shown below. This is standard will paginate functionality:
<%= js_will_paginate @recipes, :params => { :my_excluded_param => nil } %>
Hope that solves your problem.
Update 1: Added a explanation of how this works to the original question where I posted this solution.
Update 2: I've made it Rails 4 compatible with remote: true links and renamed the helper method to js_will_paginate.
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…