Edit (February 19, 2017): I received a very comprehensive reply from Mike Hearn regarding this issue:
Like in Java, what happens in Kotlin varies in different cases.
- If the lambda is passed to an inline function and isn't marked noinline, then the whole thing boils away and no additional classes or
objects are created.
- If the lambda doesn't capture, then it'll be emitted as a singleton class whose instance is reused again and again (one class+one object
allocation).
- If the lambda captures then a new object is created each time the lambda is used.
Thus it is similar behaviour to Java except for the inlining case
where it's even cheaper. This efficient approach to encoding lambdas
is one reason why functional programming in Kotlin is more attractive
than in Java.
Edit (February 17, 2017): I've posted a question regarding this topic in the Kotlin discussions. Maybe Kotlin engineers will bring something new to the table.
are kotlin lambdas simply converted to Java Anonymous functions ?
I was asking this question myself (one simple correction here: these are called Anonymous Classes, not functions). There is no clear answer in the Koltin
documentation. They just state that
Using higher-order functions imposes certain runtime penalties: each
function is an object, and it captures a closure, i.e. those variables
that are accessed in the body of the function.
It is a bit confusing what they mean by variables that are accessed in the body of the function. Is the reference to the instance of the enclosing class also counted?
I've seen the topic you are referencing in your question but it seems it is outdated as for now. I've found more up-to-date information here:
Lambda expression or anonymous function keep an implicit reference of
the enclosing class
So, unfortunately, it seems that Kotlin's lambdas have the same problems as Java's Anonymous Inner Classes.
Why Anonymous Inner Classes are bad?
From the Java
specs:
An instance i of a direct inner class C of a class O is associated
with an instance of O, known as the immediately enclosing instance of
i. The immediately enclosing instance of an object, if any, is
determined when the object is created
What this means is that the anonymous class will always have an implicit reference to the instance of the enclosing class. And since the reference is implicit there is no way to get rid of it.
Look at the trivial example
public class YourActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
new Thread(new Runnable() {
// the inner class will keep the implicit reference to the outer activity
@Override
public void run() {
// long-running task
}
}).start();
}
}
As you can see, in this case there will be the memory leak until the long-running task is executed. One workaround for this is to use static nested class.
Since Kotlin's
non-inlined lambdas hold the reference to the instance of the enclosing class they have similar issues regarding memory leaks.
Bonus: Quick Comparison With Other Lambda Implementations
Java 8 Lambdas
Syntax:
Declare SAM (single abstract method) interface
interface Runnable { void run(); }
Use this interface as a type for a lambda
public void canTakeLambda(Runnable r) { ... }
Pass your lambda
canTakeLambda(() -> System.out.println("Do work in lambda..."));
Memory leak issues: As stated in specs:
References to this -- including implicit references through
unqualified field references or method invocations -- are,
essentially, references to a final local variable. Lambda bodies that
contain such references capture the appropriate instance of this. In
other cases, no reference to this is retained by the object.
Simply put, if you do not use any fields / methods from the enclosing class there is no implicit reference to this
as in the case of anonymous classes.
Retrolambda
From the docs
Lambda expressions are backported by converting them to anonymous
inner classes. This includes the optimization of using a singleton
instance for stateless lambda expressions to avoid repeated object
allocation.
I guess, it's self-explanatory.
Apple's Swift
Syntax:
Declaration is similar to Kotlin, in Swift lambdas are called closures:
func someFunctionThatTakesAClosure(closure: (String) -> Void) {}
Pass the closure
someFunctionThatTakesAClosure { print($0) }
Here, $0
refer to the closure’s first String
argument. This corresponds to it
in Kotlin. Note: Unlike Kotlin, in Swift we can refer also to the other arguments like $1
, $2
etc.
Memory leak issues:
In Swift, just like in Java 8, the closure captures a strong reference to self
(this
in Java and Kotlin) only if it accesses a property of the instance, such as self.someProperty
, or if the closure calls a method on the instance, such as self.someMethod()
.
Also developers can easily specify that they want to capture only the weak reference:
someFunctionThatTakesAClosure { [weak self] in print($0) }
I wish it were possible in Kotlin too :)