Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
551 views
in Technique[技术] by (71.8m points)

performance - How to set initial size for a dictionary in Python?

I'm putting around 4 million different keys into a Python dictionary. Creating this dictionary takes about 15 minutes and consumes about 4GB of memory on my machine. After the dictionary is fully created, querying the dictionary is fast.

I suspect that dictionary creation is so resource consuming because the dictionary is very often rehashed (as it grows enormously). Is is possible to create a dictionary in Python with some initial size or bucket number?

My dictionary points from a number to an object.

class MyObject:
    def __init__(self):
        # some fields...

d = {}
d[i] = MyObject()  # 4M times on different key...
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

With performance issues it's always best to measure. Here are some timings:

 d = {}
 for i in xrange(4000000):
     d[i] = None
 # 722ms

 d = dict(itertools.izip(xrange(4000000), itertools.repeat(None)))
 # 634ms

 dict.fromkeys(xrange(4000000))
 # 558ms

 s = set(xrange(4000000))
 dict.fromkeys(s)
 # Not including set construction 353ms

The last option doesn't do any resizing, it just copies the hashes from the set and increments references. As you can see, the resizing isn't taking a lot of time. It's probably your object creation that is slow.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...