A unique approach would be to reverse the array and then loop. This will work for non-numerically indexed arrays as well:
$items = array(
'one' => 'two',
'two' => 'two',
'three' => 'three'
);
$backwards = array_reverse($items);
$last_item = NULL;
foreach ($backwards as $current_item) {
if ($last_item === $current_item) {
// they match
}
$last_item = $current_item;
}
If you are still interested in using the current
and next
functions, you could do this:
$items = array('two', 'two', 'three');
$length = count($items);
for($i = 0; $i < $length - 1; ++$i) {
if (current($items) === next($items)) {
// they match
}
}
#2 is probably the best solution. Note, $i < $length - 1;
will stop the loop after comparing the last two items in the array. I put this in the loop to be explicit with the example. You should probably just calculate $length = count($items) - 1;
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