Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
323 views
in Technique[技术] by (71.8m points)

php - JQuery UI autocomplete with json and ajax

I've seen a lot of questions dealing with passing an array with label and value properties via JSON, but not much about passing strings. My problem is that I cannot seem to get my autocomplete to fill. I ran a dump function and am getting these sample values passed via JSON to the autocomplete:

0: 23456
1: 21111
2: 25698

Here's some code:

$("#auto_id").autocomplete( {
    source: function(request,response) {

        $.ajax ( {
          url: "fill_id.php",
          data: {term: request.term},
          dataType: "json",
          success: function(data) {
            //what goes here?
                 } 
    }) }
   });

Here is fill_id.php:

$param = $_GET['term'];
$options = array();


$db = new SQLite3('database/main.db');
    $results = $db->query("SELECT distinct(turninId) FROM main WHERE turninid LIKE '".$param."%'");


while ($row_id = $results->fetchArray()) {
        $options[] =  $row_id['turninId']; 
    }   
echo json_encode($options);

My autocomplete remains blank. How do I change my JSON array to fill it? Or what do I include in my ajax success function?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can stick very much to the remote demo of jQuery UI's Autocomplete: http://jqueryui.com/resources/demos/autocomplete/remote-jsonp.html

To get your results into the autocompleted list, you need to put a object with a label and a value to the response parameter (which is actually a function) inside your ajax success function:

source: function( request, response ) {
    $.ajax({
        url: "fill_id.php",
        data: {term: request.term},
        dataType: "json",
        success: function( data ) {
            response( $.map( data.myData, function( item ) {
                return {
                    label: item.title,
                    value: item.turninId
                }
            }));
        }
    });
}

But this will only work if you modify yor fill_id.php a bit:

// escape your parameters to prevent sql injection
$param   = mysql_real_escape_string($_GET['term']);
$options = array();

// fetch a title for a better user experience maybe..
$db = new SQLite3('database/main.db');
    $results = $db->query("SELECT distinct(turninId), title FROM main WHERE turninid LIKE '".$param."%'");

while ($row_id = $results->fetchArray()) {
    // more structure in data allows an easier processing
    $options['myData'][] = array(
        'turninId' => $row_id['turninId'],
        'title'    => $row_id['title']
    ); 
}

// modify your http header to json, to help browsers to naturally handle your response with
header('Cache-Control: no-cache, must-revalidate');
header('Expires: Mon, 26 Jul 1997 05:00:00 GMT');
header('Content-type: application/json');

echo json_encode($options);

Of course, when you don't have a title or anything in your table, you can also just leave your response as it is and repeat the id in your success callback. Important is, that you fill your response function in the autocomplete with a value/item pair:

// this will probably work without modifying your php file at all:
response( $.map( data, function( item ) {
    return {
        label: item,
        value: item
    }
}));

edit: updated the reference link to the new jquery UI's autocomplete ui


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...