Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
386 views
in Technique[技术] by (71.8m points)

python - Integrate 2D kernel density estimate

I have a x,y distribution of points for which I obtain the KDE through scipy.stats.gaussian_kde. This is my code and how the output looks (the x,y data can be obtained from here):

import numpy as np
from scipy import stats

# Obtain data from file.
data = np.loadtxt('data.dat', unpack=True)
m1, m2 = data[0], data[1]
xmin, xmax = min(m1), max(m1)
ymin, ymax = min(m2), max(m2)

# Perform a kernel density estimate (KDE) on the data
x, y = np.mgrid[xmin:xmax:100j, ymin:ymax:100j]
positions = np.vstack([x.ravel(), y.ravel()])
values = np.vstack([m1, m2])
kernel = stats.gaussian_kde(values)
f = np.reshape(kernel(positions).T, x.shape)

# Define the number that will determine the integration limits
x1, y1 = 2.5, 1.5

# Perform integration?

# Plot the results:
import matplotlib.pyplot as plt
# Set limits
plt.xlim(xmin,xmax)
plt.ylim(ymin,ymax)
# KDE density plot
plt.imshow(np.rot90(f), cmap=plt.cm.gist_earth_r, extent=[xmin, xmax, ymin, ymax])
# Draw contour lines
cset = plt.contour(x,y,f)
plt.clabel(cset, inline=1, fontsize=10)
plt.colorbar()
# Plot point
plt.scatter(x1, y1, c='r', s=35)
plt.show()

result

The red point with coordinates (x1, y1) has (like every point in the 2D plot) an associated value given by f (the kernel or KDE) between 0 and 0.42. Let's say that f(x1, y1) = 0.08.

I need to integrate f with integration limits in x and y given by those regions where f evaluates to less than f(x1, y1), ie: f(x, y)<0.08.

For what I've seen python can perform integration of functions and one dimensional arrays through numerical integration, but I haven't seen anything that would let me perform a numerical integration on a 2D array (the f kernel) Furthermore, I'm not sure how I would even recognize the regions given by that particular condition (ie: f(x, y)less than a given value)

Can this be done at all?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Here is a way to do it using monte carlo integration. It is a little slow, and there is randomness in the solution. The error is inversely proportional to the square root of the sample size, while the running time is directly proportional to the sample size (where sample size refers to the monte carlo sample (10000 in my example below), not the size of your data set). Here is some simple code using your kernel object.

#Compute the point below which to integrate
iso = kernel((x1,y1))

#Sample from your KDE distribution
sample = kernel.resample(size=10000)

#Filter the sample
insample = kernel(sample) < iso

#The integral you want is equivalent to the probability of drawing a point 
#that gets through the filter
integral = insample.sum() / float(insample.shape[0])
print integral

I get approximately 0.2 as the answer for your data set.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...