Well. Oracle uses sequences and default values for IDENTITY functionality in 12c. Therefore you need to know about sequences for your question.
First create a test identity table.
CREATE TABLE IDENTITY_TEST_TABLE
(
ID NUMBER GENERATED ALWAYS AS IDENTITY
, NAME VARCHAR2(30 BYTE)
);
First, lets find your sequence name that is created with this identity column. This sequence name is a default value in your table.
Select TABLE_NAME, COLUMN_NAME, DATA_DEFAULT from USER_TAB_COLUMNS
where TABLE_NAME = 'IDENTITY_TEST_TABLE';
for me this value is "ISEQ$$_193606"
insert some values.
INSERT INTO IDENTITY_TEST_TABLE (name) VALUES ('atilla');
INSERT INTO IDENTITY_TEST_TABLE (name) VALUES ('ayd?n');
then insert value and find identity.
INSERT INTO IDENTITY_TEST_TABLE (name) VALUES ('atilla');
SELECT "ISEQ$$_193606".currval from dual;
you should see your identity value. If you want to do in one block use
declare
s2 number;
begin
INSERT INTO IDENTITY_TEST_TABLE (name) VALUES ('atilla') returning ID into s2;
dbms_output.put_line(s2);
end;
Last ID is my identity column name.
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