Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
428 views
in Technique[技术] by (71.8m points)

php - Displaying BLOB image from Mysql database into dynamic div in html

I have a BLOB image that is stored when the user submits an advert form, they have the choice of uploading one image. The image is stored in the database with the other information.

Every time my page loads it dynamically creates the advert divs and also fills in the matching information from my database into the div.

The problem I have is displaying all the information including the image together at the same time so when the user clicks to view the page they see each div with a different picture and information. I've seen the other posts on how to display the image but I doubt its the same method when you're displaying several images from the same database.

My database is set up as follows:

ID ADTITLE EMAIL PRICE DESCRIPTION CATEGORY name type size content DATE

The bold variables are for the image/blob

Here is my code where I retrieve the information :

$Category = 'Specials'; 
$query = $pdo->prepare("SELECT * FROM adsubm WHERE CATEGORY LIKE '%$Category%' ORDER BY DATE DESC" );
$query->execute();

while($row = $query->fetch()) {
    $Adtitle=$row['ADTITLE'];
    $Desc=$row['DESCRIPTION'];
    $Price=$row['PRICE'];
    $Date=$row['DATE'];
    $timestamp=strtotime($Date);
    $Day= date("d",$timestamp);
    $Month=date("F",$timestamp);
    $Newmonth=date('M', strtotime($Month . '01'));
    $Year=date("Y",$timestamp);
    header('Content-type: image/jpeg');
    $Image=$row['content'];


echo  " 
           <div class='[ col-xs-12 col-sm-offset-2 col-sm-8 ]' style='margin-top: 10px'>
                <ul class='event-list'>
                    <li>
                        <time datetime='$Date'>
                            <span class='day'>$Day</span>
                            <span class='month'>$Newmonth</span>
                            <span class='year'>$Year</span>
                            <span class='time'>ALL DAY</span>
                        </time>
                        <img alt='#' src='$Image/>
                        <div class='info'>
                            <h2 class='title'>$Adtitle</h2>
                            <p class='desc'>$Desc</p>
                                                        <ul>
                                <li style='width:50%;'><span class='fa fa-money'></span>  $Price</li>
                            </ul>
                        </div>

                    </li>
                              </ul>
                    </div>
        ";

My php skills are still beginner levels as well. I'm just trying to keep things as plain and simple as possible, i'll look into other methods abit later.

All help is appreciated. Thanks

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

1) Base64 option

Work with a single line, image/png for a png image and image/jpeg for a jpg one :

echo '<img src="data:image/png;base64,'.base64_encode($blob).'"/>';

example :

<div style="background-color:black; text-align:center; padding: 5px;">
  <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAADIAAAAwBAMAAACh2TSJAAAALVBMVEUAAADtNTX////3n5/+9fX719f7zMz5tLTzfHzuQED//f31jY3ybGzxXV3wVFRaxp+rAAAAAXRSTlMAQObYZgAAALVJREFUOMut0rENAjEQRNHdC4kY0QBaAQUQX0QAFSAKIKQEKiAA6VqgIkriApuV1x7pQPz0aWwHljLMpZ0CRDBGoXmeghGYKFJsUo90giAImCgV5OJF+oOgKE48MlGgs2VLBIunWesw0a1ZHqF82c7GmmIfUSpgotOly29DFPFJFDEhkgIT/V5mZuvj6XofKrHU6vyI4u37IYi36aN4h5tL7PJyif1dvCgEpapzISbCTEj5R78BZq5A5Ldh2XYAAAAASUVORK5CYII">
</div>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...