In the context of computer science, a word is the concatenation of symbols. The used symbols are called the alphabet. For example, some words formed out of the alphabet {0,1,2,3,4,5,6,7,8,9} would be 1, 2, 12, 543, 1000, and 002.
A language is then a subset of all possible words. For example, we might want to define a language that captures all elite MI6 agents. Those all start with double-0, so words in the language would be 007, 001, 005, and 0012, but not 07 or 15. For simplicity's sake, we say a language is "over an alphabet" instead of "a subset of words formed by concatenation of symbols in an alphabet".
In computer science, we now want to classify languages. We call a language regular if it can be decided if a word is in the language with an algorithm/a machine with constant (finite) memory by examining all symbols in the word one after another. The language consisting just of the word 42 is regular, as you can decide whether a word is in it without requiring arbitrary amounts of memory; you just check whether the first symbol is 4, whether the second is 2, and whether any more numbers follow.
All languages with a finite number of words are regular, because we can (in theory) just build a control flow tree of constant size (you can visualize it as a bunch of nested if-statements that examine one digit after the other). For example, we can test whether a word is in the "prime numbers between 10 and 99" language with the following construct, requiring no memory except the one to encode at which code line we're currently at:
if word[0] == 1:
if word[1] == 1: # 11
return true # "accept" word, i.e. it's in the language
if word[1] == 3: # 13
return true
...
return false
Note that all finite languages are regular, but not all regular languages are finite; our double-0 language contains an infinite number of words (007, 008, but also 004242 and 0012345), but can be tested with constant memory: To test whether a word belongs in it, check whether the first symbol is 0, and whether the second symbol is 0. If that's the case, accept it. If the word is shorter than three or does not start with 00, it's not an MI6 code name.
Formally, the construct of a finite-state machine or a regular grammar is used to prove that a language is regular. These are similar to the if-statements above, but allow for arbitrarily long words. If there's a finite-state machine, there is also a regular grammar, and vice versa, so it's sufficient to show either. For example, the finite state machine for our double-0 language is:
start state: if input = 0 then goto state 2
start state: if input = 1 then fail
start state: if input = 2 then fail
...
state 2: if input = 0 then accept
state 2: if input != 0 then fail
accept: for any input, accept
The equivalent regular grammar is:
start → 0 B
B → 0 accept
accept → 0 accept
accept → 1 accept
...
The equivalent regular expression is:
00[0-9]*
Some languages are not regular. For example, the language of any number of 1, followed by the same number of 2 (often written as 1n2n, for an arbitrary n) is not regular - you need more than a constant amount of memory (= a constant number of states) to store the number of 1s to decide whether a word is in the language.
This should usually be explained in the theoretical computer science course. Luckily, Wikipedia explains both formal and regular languages quite nicely.
