Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
199 views
in Technique[技术] by (71.8m points)

ios - swift : Closure declaration as like block declaration

We can declare block as below in Objective-C.

typedef void (^CompletionBlock) (NSString* completionReason);

I'm trying to do this in swift, it give error.

func completionFunction(NSString* completionReason){ }
typealias CompletionBlock = completionFunction

Error : Use of undeclared 'completionFunction'

Definition :

var completion: CompletionBlock = { }

How to do this?

Update:

According to @jtbandes's answer, I can create closure with multiple arguments as like

typealias CompletionBlock = ( completionName : NSString, flag : Int) -> ()
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The syntax for function types is (in) -> out.

typealias CompletionBlock = (NSString?) -> Void
// or
typealias CompletionBlock = (result: NSData?, error: NSError?) -> Void
var completion: CompletionBlock = { reason in print(reason) }
var completion: CompletionBlock = { result, error in print(error) }

Note that the parentheses around the input type are only required as of Swift 3+.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...