Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
556 views
in Technique[技术] by (71.8m points)

lambda - Stream.peek() method in Java 8 vs Java 9

I am in the progress of learning through Java 8 lambda expressions and would like to ask about the following piece of Java code relating to the peek method in the function interface that I have come across.

On execution of the program on IDE, it gives no output. I was expecting it would give 2, 4, 6.

import java.util.Arrays;
import java.util.List;

public class Test_Q3 {

    public Test_Q3() {
    }

    public static void main(String[] args) {
        List<Integer> values = Arrays.asList(1, 2, 3);
        values.stream()
              .map(n -> n * 2)
              .peek(System.out::print)
              .count();
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I assume you are running this under Java 9? You are not altering the SIZED property of the stream, so there is no need to execute either map or peek at all.

In other words all you care is about count as the final result, but in the meanwhile you do not alter the initial size of the List in any way (via filter for example or distinct) This is an optimization done in the Streams.

Btw, even if you add a dummy filter this will show what you expect:

values.stream ()
      .map(n -> n*2)
      .peek(System.out::print)
      .filter(x -> true)
      .count();

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...