go - Why would a call to fmt.Sprint(e) inside the Error() method result in an infinite loop?

Question

I am going through "A Tour of Go" tutorial.

I would like to check the answer to this question:

Note: a call to fmt.Sprint(e) inside the Error method will send the program into an infinite loop. You can avoid this by converting e first: fmt.Sprint(float64(e)). Why?

I believe this is because when the Sprint function is called, since the error is non-nil, the Error function() will again be called, and so forth, resulting in an infinite loop.

Answer 1

Waitting for answers