Using str.format
:
>>> array_alpha = [ 133, 53, 234, 241 ]
>>> print ''.join('{:02x}'.format(x) for x in array_alpha)
8535eaf1
or using format
>>> print ''.join(format(x, '02x') for x in array_alpha)
8535eaf1
Note: In the format statements, the 02
means it will pad with up to 2 leading 0
s if necessary. This is important since [0x1, 0x1, 0x1] i.e. (0x010101)
would be formatted to "111"
instead of "010101"
or using bytearray
with binascii.hexlify
:
>>> import binascii
>>> binascii.hexlify(bytearray(array_alpha))
'8535eaf1'
Here is a benchmark of above methods in Python 3.6.1:
from timeit import timeit
import binascii
number = 10000
def using_str_format() -> str:
return "".join("{:02x}".format(x) for x in test_obj)
def using_format() -> str:
return "".join(format(x, "02x") for x in test_obj)
def using_hexlify() -> str:
return binascii.hexlify(bytearray(test_obj)).decode('ascii')
def do_test():
print("Testing with {}-byte {}:".format(len(test_obj), test_obj.__class__.__name__))
if using_str_format() != using_format() != using_hexlify():
raise RuntimeError("Results are not the same")
print("Using str.format -> " + str(timeit(using_str_format, number=number)))
print("Using format -> " + str(timeit(using_format, number=number)))
print("Using binascii.hexlify -> " + str(timeit(using_hexlify, number=number)))
test_obj = bytes([i for i in range(255)])
do_test()
test_obj = bytearray([i for i in range(255)])
do_test()
Result:
Testing with 255-byte bytes:
Using str.format -> 1.459474583090427
Using format -> 1.5809937679100738
Using binascii.hexlify -> 0.014521426401399307
Testing with 255-byte bytearray:
Using str.format -> 1.443447684109402
Using format -> 1.5608712609513171
Using binascii.hexlify -> 0.014114164661833684
Methods using format
do provide additional formatting options, as example separating numbers with spaces " ".join
, commas ", ".join
, upper-case printing "{:02X}".format(x)
/format(x, "02X")
, etc., but at a cost of great performance impact.
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