import itertools
output = list(itertools.islice(q, 3, 7))
For example:
>>> import collections, itertools
>>> q = collections.deque(xrange(10, 20))
>>> q
deque([10, 11, 12, 13, 14, 15, 16, 17, 18, 19])
>>> list(itertools.islice(q, 3, 7))
[13, 14, 15, 16]
This should be more efficient the the other solutions posted so far. Proof?
[me@home]$ SETUP="import itertools,collections; q=collections.deque(xrange(1000000))"
[me@home]$ python -m timeit "$SETUP" "list(itertools.islice(q, 10000, 20000))"
10 loops, best of 3: 68 msec per loop
[me@home]$ python -m timeit "$SETUP" "[q[i] for i in xrange(10000, 20000)]"
10 loops, best of 3: 98.4 msec per loop
[me@home]$ python -m timeit "$SETUP" "list(q)[10000:20000]"
10 loops, best of 3: 107 msec per loop
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