Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
174 views
in Technique[技术] by (71.8m points)

php - How can I build a condition based query in Laravel?

I can do this in Code Igniter:

$this->db->select();
$this->from->('node');
if ($published == true)
{
    $this->db->where('published', 'true');
}
if (isset($year))
{
    $this->db->where('year >', $year);
}
$this->db->get();

How can this code be translated so that it works in Laravel?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

In Fluent you can do:

$query = DB::table('node');

if ($published == true)
    $query->where('published', '=', 1);

if (isset($year))
    $query->where('year', '>', $year);

$result = $query->get();

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...