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in Technique[技术] by (71.8m points)

nodejs express 中,throw 一个异常,如何指定响应号?

throw new Error('asdasdad')

这样会返回
{

error: asdasdad,
error_code: 500,

}

如何指定error_code呢?

例如 throw new Error('asdasdad', 400)


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by (71.8m points)

自己写一个class继承自Error就可以了。比如:

export default class ApiError extends Error {
  constructor(msg, code) {
    super(msg);
    this.msg = msg;
    this.code = code;
  }
}


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