I have a list of items that I want to fit in a space that is constrained vertically:
<ul>
<li>One</li>
<li>Two</li>
<li>Three</li>
<li>Four</li>
<li>Five</li>
<li>Six</li>
</ul>
Since I don't want the list to have more than a specific height, but I'm free to expan it horizontally, I want to divide the list into columns, like this:
One Two Three
Four Five Six
Or, alternatively (in my case order is not important)
One Three Five
Two Four Six
The css property column-count
allows to break a list into columns, but it only accepts a fixed number of columns. I don't know the number of items I am going to have (it can go from 1 to more than 40), so if I set the number of columns to 3, any list with more than 6 items will be too high, and if there is only 4 items, then only the first column will have two items and it will look uneven.
So, ideally I would need a row-count
property, but it doesn't exist. I guess I can do that in Javascript too but I'm looking for a CSS-only solution.
I tried something: float:left
on every li
puts the list in one row. To break it into two rows, I would need to not apply float:left
to the N/2 element. I don't know how to do that.
I know also that I can do it by breaking it into multiple ul
, each one with two li
, and float:left
them, but I would like to avoid messing the HTML for something entirely presentational.
Does someone has a solution for this problem?
Edit: I think I have not been clear in explaining my requirements. I want the list to be sorted into columns without knowing how many items I'm going to have, and so that I will always have two rows.
So for example with 7 items, I want to have:
One Two Three Four
Five Six Seven
And with 3 items:
One Two
Three
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