Assuming you have an ordering column -- say id
-- then you can do the following in SQL Server 2012:
select col,
col - coalesce(lag(col) over (order by id), 0) as diff
from t;
In earlier versions of SQL Server, you can do almost the same thing using a correlated subquery:
select col,
col - isnull((select top 1 col
from t t2
where t2.id < t.id
order by id desc
), 0)
from t
This uses isnull()
instead of coalesce()
because of a "bug" in SQL Server that evaluates the first argument twice when using coalesce()
.
You can also do this with row_number()
:
with cte as (
select col, row_number() over (order by id) as seqnum
from t
)
select t.col, t.col - coalesce(tprev.col, 0) as diff
from cte t left outer join
cte tprev
on t.seqnum = tprev.seqnum + 1;
All of these assume that you have some column for specifying the ordering. It might be an id
, or a creation date or something else. SQL tables are inherently unordered, so there is no such thing as a "previous row" without a column specifying the ordering.
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