If convenient, change your directory structure; but if not, you can use ctypes to call opendir
and readdir
.
Here is a copy of that code; all I did was indent it properly, add the try/finally
block, and fix a bug. You might have to debug it. Particularly the struct layout.
Note that this code is not portable. You would need to use different functions on Windows, and I think the structs vary from Unix to Unix.
#!/usr/bin/python
"""
An equivalent os.listdir but as a generator using ctypes
"""
from ctypes import CDLL, c_char_p, c_int, c_long, c_ushort, c_byte, c_char, Structure, POINTER
from ctypes.util import find_library
class c_dir(Structure):
"""Opaque type for directory entries, corresponds to struct DIR"""
pass
c_dir_p = POINTER(c_dir)
class c_dirent(Structure):
"""Directory entry"""
# FIXME not sure these are the exactly correct types!
_fields_ = (
('d_ino', c_long), # inode number
('d_off', c_long), # offset to the next dirent
('d_reclen', c_ushort), # length of this record
('d_type', c_byte), # type of file; not supported by all file system types
('d_name', c_char * 4096) # filename
)
c_dirent_p = POINTER(c_dirent)
c_lib = CDLL(find_library("c"))
opendir = c_lib.opendir
opendir.argtypes = [c_char_p]
opendir.restype = c_dir_p
# FIXME Should probably use readdir_r here
readdir = c_lib.readdir
readdir.argtypes = [c_dir_p]
readdir.restype = c_dirent_p
closedir = c_lib.closedir
closedir.argtypes = [c_dir_p]
closedir.restype = c_int
def listdir(path):
"""
A generator to return the names of files in the directory passed in
"""
dir_p = opendir(path)
try:
while True:
p = readdir(dir_p)
if not p:
break
name = p.contents.d_name
if name not in (".", ".."):
yield name
finally:
closedir(dir_p)
if __name__ == "__main__":
for name in listdir("."):
print name
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