I'm using Visual Studio c++ Compiler ( 2010 ), but the library has different implementation of ANSI C and POSIX libraries function.
What is the difference between ANSI C function and Windows CRT implementation? For example what is the difference between tzset()
and _tzset()
or setenv()
ans _setenv()
? It seems the do the same thing in the same way...
I'm using msvc ( 2010 ), have I to prefer the Windows CRT Implementation?
EDIT 1
Well I want convert in a portable way a struct tm expressed in UTC in a time_t
, but there's no portable way to do that. I've to write the function for different platform (Android, Linux, Windows, Windows CE ).
I've seen this stackoverflow post that uses setenv
, getenv
and tzset
Edit2
Unfortunately after some test I've discovered that getenv("TZ")
returns a null pointer on windows. But why is so difficult transform a UTC time struct to a time_t
?
Edit 3
From Boost I discovered this fragment of code in boost/chrono/io/time_point_io.hpp. Hope this helps me.
inline int32_t is_leap(int32_t year)
{
if(year % 400 == 0)
return 1;
if(year % 100 == 0)
return 0;
if(year % 4 == 0)
return 1;
return 0;
}
inline int32_t days_from_0(int32_t year)
{
year--;
return 365 * year + (year / 400) - (year/100) + (year / 4);
}
inline int32_t days_from_1970(int32_t year)
{
static const int days_from_0_to_1970 = days_from_0(1970);
return days_from_0(year) - days_from_0_to_1970;
}
inline int32_t days_from_1jan(int32_t year,int32_t month,int32_t day)
{
static const int32_t days[2][12] =
{
{ 0,31,59,90,120,151,181,212,243,273,304,334},
{ 0,31,60,91,121,152,182,213,244,274,305,335}
};
return days[is_leap(year)][month-1] + day - 1;
}
inline time_t internal_timegm(std::tm const *t)
{
int year = t->tm_year + 1900;
int month = t->tm_mon;
if(month > 11)
{
year += month/12;
month %= 12;
}
else if(month < 0)
{
int years_diff = (-month + 11)/12;
year -= years_diff;
month+=12 * years_diff;
}
month++;
int day = t->tm_mday;
int day_of_year = days_from_1jan(year,month,day);
int days_since_epoch = days_from_1970(year) + day_of_year;
time_t seconds_in_day = 3600 * 24;
time_t result = seconds_in_day * days_since_epoch + 3600 * t->tm_hour + 60 * t->tm_min + t->tm_sec;
return result;
}
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