It's hard to implement this efficiently with a SortedDictionary<TKey, TValue>
since it is implemented as a binary search tree that does not expose predecessors or successors.
You could of course just enumerate each KeyValuePair until you find the "known" key. With a little bit of LINQ, this would look like (assuming the key definitely exists and isn't the first key):
SortedDictionary<int, int> dictionary = ...
int knownKey = ...
var previousKvp = dictionary.TakeWhile(kvp => kvp.Key != knownKey)
.Last();
If those assumptions don't hold, you could do:
var maybePreviousKvp = dictionary.TakeWhile(kvp => kvp.Key != knownKey)
.Cast<KeyValuePair<int, int>?>()
.LastOrDefault();
(Check that maybePreviousKvp != null
to ascertain that the previous KeyValuePair was retrieved successfully.)
But this isn't going to be efficient at all.
If feasible, consider using a SortedList<TKey, TValue>
instead (obviously, this may not be possible if you can't take its slower inserts and deletes). This collection supports efficient key and value-retrieval by ordered index since it is implemented as a growable array. Then your query becomes as simple as:
SortedList<int, int> dictionary = ...
int knownKey = ...
int indexOfPrevious = dictionary.IndexOfKey(knownKey) - 1;
// if "known" key exists and isn't the first key
if(indexOfPrevious >= 0)
{
// Wrap these in a KeyValuePair if necessary
int previousKey = dictionary.Keys[indexOfPrevious];
int previousValue = dictionary.Values[indexOfPrevious];
}
IndexOfKey
runs a binary search on the keys-list, running in O(log n)
time. Everything else should run in constant time, meaning the entire operation should run in logarithmic time.
Otherwise, you'll have to implement yourself / find a BST collection that does expose predecessors / successors.
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