Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
325 views
in Technique[技术] by (71.8m points)

c++ - What should happen to the negation of a size_t (i.e. `-sizeof(struct foo)`))?

I'm dealing with some code at work that includes an expression of the form

-(sizeof(struct foo))

i.e. the negation of a size_t, and I'm unclear on what the C and C++ standards require of compilers when they see this. Specifically, from looking around here and elsewhere, sizeof returns an unsigned integral value of type size_t. I can't find any clear reference for specified behavior when negating an unsigned integer. Is there any, and if so, what is it?

Edit: Ok, so there are some good answers regarding arithmetic on unsigned types, but it's not clear that this is in fact such. When this negates, is it operating on an unsigned integer, or converting to a signed type and doing something with that? Is the behavior to expect from the standards "imagine it's the negative number of similar magnitude and then apply the 'overflow' rules for unsigned values"?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Both ISO C and ISO C++ standards guarantee that unsigned arithmetic is modulo 2n - i.e., for any overflow or underflow, it "wraps around". For ISO C++, this is 3.9.1[basic.fundamental]/4:

Unsigned integers, declared unsigned, shall obey the laws of arithmetic modulo 2n where n is the number of bits in the value representation of that particular size of integer.41

...

41) This implies that unsigned arithmetic does not overflow because a result that cannot be represented by the resulting unsigned integer type is reduced modulo the number that is one greater than the largest value that can be represented by the resulting unsigned integer type.

For ISO C(99), it is 6.2.5/9:

A computation involving unsigned operands can never overflow, because a result that cannot be represented by the resulting unsigned integer type is reduced modulo the number that is one greater than the largest value that can be represented by the resulting type.

Which means the result is guaranteed to be the same as SIZE_MAX - (sizeof(struct foo)) + 1.


In ISO 14882:2003 5.3.1.7:

[...] The negative of an unsigned quantity is computed by subtracting its value from 2n, where n is the number of bits in the pro- moted operand. The type of the result is the type of the promoted operand.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...