In .Net 4 or 4.5, how would you design a serializable class that contains an instance of one class from a set of classes? For instance, suppose I have a Garage class, which can hold an instance of any "vehicle" type classes, say Car, Boat, Motorcycle, Motorhome. But the Garage can only hold an instance of one of those classes. I have tried a few different ways of doing this, but my problem is to make it serializable.
Here is a starting example where there is only one option for the instance in the Garage class. You should be able to plug it right into a new console app and try it.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
namespace Patterns
{
[Serializable()]
public class Garage
{
private Vehicle _MyVehicle;
public Garage()
{
}
public string GarageOwner { get; set; }
public Vehicle MyVehicle
{
get { return _MyVehicle; }
set { _MyVehicle = value; }
}
}
[Serializable()]
public class Vehicle
{
public string VehicleType { get; set; }
public int VehicleNumber { get; set; }
}
class Serializer
{
static string _StartupPath = @"C:ProjectsPatternsData";
static string _StartupFile = "SerializerTest.xml";
static string _StartupXML = _StartupPath + _StartupFile;
static void Main(string[] args)
{
Console.Write("Press w for write. Press r for read:");
ConsoleKeyInfo cki = Console.ReadKey(true);
Console.WriteLine("Pressed: " + cki.KeyChar.ToString());
if (cki.KeyChar.ToString() == "w")
{
Garage MyGarage = new Garage();
MyGarage.GarageOwner = "John";
MyGarage.MyVehicle = new Vehicle();
MyGarage.MyVehicle.VehicleType = "Car";
MyGarage.MyVehicle.VehicleNumber = 1234;
WriteGarageXML(MyGarage);
Console.WriteLine("Serialized");
}
else if (cki.KeyChar.ToString() == "r")
{
Garage MyGarage = ReadGarageXML();
Console.WriteLine("Deserialized Garage owned by " + MyGarage.GarageOwner);
}
Console.ReadKey();
}
public static void WriteGarageXML(Garage pInstance)
{
XmlSerializer writer = new XmlSerializer(typeof(Garage));
using (FileStream file = File.OpenWrite(_StartupXML))
{
writer.Serialize(file, pInstance);
}
}
public static Garage ReadGarageXML()
{
XmlSerializer reader = new XmlSerializer(typeof(Garage));
using (FileStream input = File.OpenRead(_StartupXML))
{
return reader.Deserialize(input) as Garage;
}
}
}
}
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