Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
391 views
in Technique[技术] by (71.8m points)

angle attribute in android gradient

I am going through test example. Where for some Image background they are using gradient, the code goes like this

<?xml version="1.0" encoding="utf-8"?>


  <shape xmlns:android="http://schemas.android.com/apk/res/android">
    <gradient
        android:startColor="#ff0000"
        android:centerColor="#00ff00"
        android:endColor="#0000ff"
        android:angle="180"/>
    <corners android:radius="5dp" />
   </shape>

In the above xml I didn't get angle attribute. but when I change the value of angle slightly the pattern slants. Can anyone explain me how exactly it works?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Gradient basically represents the variation in space(in a direction) of any quantity. With color it represents the variation of color intensity in a direction represented by angle. Here are some diagrams to represent this concept:
enter image description here

Here the figure shows the color variation in horizontal direction (angle is set 0).
XML code:

    <shape xmlns:android="http://schemas.android.com/apk/res/android">
    <gradient
        android:startColor="#000000"
        android:angle="0"/>
   </shape>

enter image description here

Here the figure shows the color variation in vertical direction (angle is set 90).
XML code:

<shape xmlns:android="http://schemas.android.com/apk/res/android">
<gradient
    android:startColor="#000000"
    android:angle="90"/>
 </shape>

You can also use different color as start, center and end colors. The code you attached contains all these elements.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...