Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
320 views
in Technique[技术] by (71.8m points)

python - Scatterplot Contours In Matplotlib

I have a massive scatterplot (~100,000 points) that I'm generating in matplotlib. Each point has a location in this x/y space, and I'd like to generate contours containing certain percentiles of the total number of points.

Is there a function in matplotlib which will do this? I've looked into contour(), but I'd have to write my own function to work in this way.

Thanks!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Basically, you're wanting a density estimate of some sort. There multiple ways to do this:

  1. Use a 2D histogram of some sort (e.g. matplotlib.pyplot.hist2d or matplotlib.pyplot.hexbin) (You could also display the results as contours--just use numpy.histogram2d and then contour the resulting array.)

  2. Make a kernel-density estimate (KDE) and contour the results. A KDE is essentially a smoothed histogram. Instead of a point falling into a particular bin, it adds a weight to surrounding bins (usually in the shape of a gaussian "bell curve").

Using a 2D histogram is simple and easy to understand, but fundementally gives "blocky" results.

There are some wrinkles to doing the second one "correctly" (i.e. there's no one correct way). I won't go into the details here, but if you want to interpret the results statistically, you need to read up on it (particularly the bandwidth selection).

At any rate, here's an example of the differences. I'm going to plot each one similarly, so I won't use contours, but you could just as easily plot the 2D histogram or gaussian KDE using a contour plot:

import numpy as np
import matplotlib.pyplot as plt
from scipy.stats import kde

np.random.seed(1977)

# Generate 200 correlated x,y points
data = np.random.multivariate_normal([0, 0], [[1, 0.5], [0.5, 3]], 200)
x, y = data.T

nbins = 20

fig, axes = plt.subplots(ncols=2, nrows=2, sharex=True, sharey=True)

axes[0, 0].set_title('Scatterplot')
axes[0, 0].plot(x, y, 'ko')

axes[0, 1].set_title('Hexbin plot')
axes[0, 1].hexbin(x, y, gridsize=nbins)

axes[1, 0].set_title('2D Histogram')
axes[1, 0].hist2d(x, y, bins=nbins)

# Evaluate a gaussian kde on a regular grid of nbins x nbins over data extents
k = kde.gaussian_kde(data.T)
xi, yi = np.mgrid[x.min():x.max():nbins*1j, y.min():y.max():nbins*1j]
zi = k(np.vstack([xi.flatten(), yi.flatten()]))

axes[1, 1].set_title('Gaussian KDE')
axes[1, 1].pcolormesh(xi, yi, zi.reshape(xi.shape))

fig.tight_layout()
plt.show()

enter image description here

One caveat: With very large numbers of points, scipy.stats.gaussian_kde will become very slow. It's fairly easy to speed it up by making an approximation--just take the 2D histogram and blur it with a guassian filter of the right radius and covariance. I can give an example if you'd like.

One other caveat: If you're doing this in a non-cartesian coordinate system, none of these methods apply! Getting density estimates on a spherical shell is a bit more complicated.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...