Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
560 views
in Technique[技术] by (71.8m points)

unicode - JavaScript: how to check if character is RTL?

How can I programmatically check if the browser treats some character as RTL in JavaScript?

Maybe creating some transparent DIV and looking at where text is placed?

A bit of context. Unicode 5.2 added Avestan alphabet support. So, if the browser has Unicode 5.2 support, it treats characters like U+10B00 as RTL (currently only Firefox does). Otherwise, it treats these characters as LTR, because this is the default.

How do I programmatically check this? I'm writing an Avestan input script and I want to override the bidi direction if the browser is too dumb. But, if browser does support Unicode, bidi settings shouldn't be overriden (since this will allow mixing Avestan and Cyrillic).

I currently do this:

var ua = navigator.userAgent.toLowerCase();

if (ua.match('webkit') || ua.match('presto') || ua.match('trident')) {
    var input = document.getElementById('orig');
    if (input) {
        input.style.direction = 'rtl';
        input.style.unicodeBidi = 'bidi-override';
    }
}

But, obviously, this would render script less usable after Chrome and Opera start supporting Unicode 5.2.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
function isRTL(s){           
    var ltrChars    = 'A-Za-zu00C0-u00D6u00D8-u00F6u00F8-u02B8u0300-u0590u0800-u1FFF'+'u2C00-uFB1CuFDFE-uFE6FuFEFD-uFFFF',
        rtlChars    = 'u0591-u07FFuFB1D-uFDFDuFE70-uFEFC',
        rtlDirCheck = new RegExp('^[^'+ltrChars+']*['+rtlChars+']');

    return rtlDirCheck.test(s);
};

playground page


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...