This query will not give you duplicates - ie, it will give you all the rows in the database, ordered by email.
However, I presume what you mean is that you have duplicate data within your database. Adding distinct()
here won't help, because even if you have only one field, you also have an automatic id
field - so the combination of id+email is not unique.
Assuming you only need one field, email_address
, de-duplicated, you can do this:
email_list = Email.objects.values_list('email', flat=True).distinct()
However, you should really fix the root problem, and remove the duplicate data from your database.
Example, deleting duplicate Emails by email field:
for email in Email.objects.values_list('email', flat=True).distinct():
Email.objects.filter(pk__in=Email.objects.filter(email=email).values_list('id', flat=True)[1:]).delete()
Or books by name:
for name in Book.objects.values_list('name', flat=True).distinct():
Book.objects.filter(pk__in=Artwork.objects.filter(name=name).values_list('id', flat=True)[3:]).delete()
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