shell - How to compare two decimal numbers in bash/awk?

Question

I am trying to compare two decimal values but I am getting errors. I used

if [ "$(echo $result1 '>' $result2 | bc -l)" -eq 1 ];then

as suggested by the other Stack Overflow thread.

I am getting errors.

What is the correct way to go about this?

Answer 1

You can do it using Bash's numeric context:

if (( $(echo "$result1 > $result2" | bc -l) )); then

bc will output 0 or 1 and the (( )) will interpret them as false or true respectively.

The same thing using AWK:

if (( $(echo "$result1 $result2" | awk '{print ($1 > $2)}') )); then