Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
248 views
in Technique[技术] by (71.8m points)

c++ - What is the difference between std::shared_ptr and std::experimental::atomic_shared_ptr?

I read the following article by Antony Williams and as I understood in addition to the atomic shared count in std::shared_ptr in std::experimental::atomic_shared_ptr the actual pointer to the shared object is also atomic?

But when I read about reference counted version of lock_free_stack described in Antony's book about C++ Concurrency it seems for me that the same aplies also for std::shared_ptr, because functions like std::atomic_load, std::atomic_compare_exchnage_weak are applied to the instances of std::shared_ptr.

template <class T>
class lock_free_stack
{
public:
  void push(const T& data)
  {
    const std::shared_ptr<node> new_node = std::make_shared<node>(data);
    new_node->next = std::atomic_load(&head_);
    while (!std::atomic_compare_exchange_weak(&head_, &new_node->next, new_node));
  }

  std::shared_ptr<T> pop()
  {
    std::shared_ptr<node> old_head = std::atomic_load(&head_);
    while(old_head &&
          !std::atomic_compare_exchange_weak(&head_, &old_head, old_head->next));
    return old_head ? old_head->data : std::shared_ptr<T>();
  }

private:
  struct node
  {
    std::shared_ptr<T> data;
    std::shared_ptr<node> next;

    node(const T& data_) : data(std::make_shared<T>(data_)) {}
  };

private:
  std::shared_ptr<node> head_;
};

What is the exact difference between this two types of smart pointers, and if pointer in std::shared_ptr instance is not atomic, why it is possible the above lock free stack implementation?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The atomic "thing" in shared_ptr is not the shared pointer itself, but the control block it points to. meaning that as long as you don't mutate the shared_ptr across multiple threads, you are ok. do note that copying a shared_ptr only mutates the control block, and not the shared_ptr itself.

std::shared_ptr<int> ptr = std::make_shared<int>(4);
for (auto i =0;i<10;i++){
   std::thread([ptr]{ auto copy = ptr; }).detach(); //ok, only mutates the control block 
}

Mutating the shared pointer itself, such as assigning it different values from multiple threads, is a data race, for example:

std::shared_ptr<int> ptr = std::make_shared<int>(4);
std::thread threadA([&ptr]{
   ptr = std::make_shared<int>(10);
});
std::thread threadB([&ptr]{
   ptr = std::make_shared<int>(20);
});    

Here, we are mutating the control block (which is ok) but also the shared pointer itself, by making it point to a different values from multiple threads. This is not ok.

A solution to that problem is to wrap the shared_ptr with a lock, but this solution is not so scalable under some contention, and in a sense, loses the automatic feeling of the standard shared pointer.

Another solution is to use the standard functions you quoted, such as std::atomic_compare_exchange_weak. This makes the work of synchronizing shared pointers a manual one, which we don't like.

This is where atomic shared pointer comes to play. You can mutate the shared pointer from multiple threads without fearing a data race and without using any locks. The standalone functions will be members ones, and their use will be much more natural for the user. This kind of pointer is extremely useful for lock-free data structures.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...