Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
887 views
in Technique[技术] by (71.8m points)

arrays - Minimum value of maximum values in sub-segments ... in O(n) complexity

I interviewed with Amazon a few days ago. I could not answer one of the questions the asked me to their satisfaction. I have tried to get the answer after the interview but I have not been successful so far. Here is the question:

You have an array of integers of size n. You are given parameter k where k < n. For each segment of consecutive elements of size k in the array you need to calculate the maximum value. You only need to return the minimum value of these maximum values.

For instance given 1 2 3 1 1 2 1 1 1 and k = 3 the answer is 1.
The segments would be 1 2 3, 2 3 1, 3 1 1, 1 1 2, 1 2 1, 2 1 1, 1 1 1.
The maximum values in each segment are 3, 3, 3, 2, 2, 2, 1.
The minimum of these values are 1 thus the answer is 1.

The best answer I came up with is of complexity O(n log k). What I do is to create a binary search tree with the first k elements, get the maximum value in the tree and save it in variable minOfMax, then loop one element at a time with the remaining elements in the array, remove the first element in the previous segment from the binary search tree, insert the last element of the new segment in the tree, get the maximum element in the tree and compare it with minOfMax leaving in minOfMax the min value of the two.

The ideal answer needs to be of complexity O(n). Thank you.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

There is a very clever way to do this that's related to this earlier question. The idea is that it's possible to build a queue data structure that supports enqueue, dequeue, and find-max in amortized O(1) time (there are many ways to do this; two are explained in the original question). Once you have this data structure, begin by adding the first k elements from the array into the queue in O(k) time. Since the queue supports O(1) find-max, you can find the maximum of these k elements in O(1) time. Then, continuously dequeue an element from the queue and enqueue (in O(1) time) the next array element. You can then query in O(1) what the maximum of each of these k-element subarrays are. If you track the minimum of these values that you see over the course of the array, then you have an O(n)-time, O(k)-space algorithm for finding the minimum maximum of the k-element subarrays.

Hope this helps!


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...