Here is a simplified table structure:
TABLE products (
product_id INT (primary key, auto_increment),
category_id INT,
product_title VARCHAR,
etc
);
TABLE product_photos (
product_photo_id (primary key, auto_increment),
product_id INT,
photo_href VARCHAR,
photo_order INT
);
A product can have multiple photos, the first product photo for each product (based on the photo_order) is the default photo.
Now, I only need all of the photos on the product details page, but on pages where I am listing multiple products, for example a product directory page, I only want to display the default photo.
So what I am trying to do, is query a list of products including the default photo for each product.
This obviously doesn't work, it will return all photos with the product info duplicated for each photo:
SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
ON p.product_id=ph.product_id
ORDER BY p.product_title ASC
I need to figure out how to do something like this, but I don't know the syntax (or if it is possible)
SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
ON p.product_id=ph.product_id **ORDER BY ph.photo_order ASC LIMIT 1**
ORDER BY p.product_title ASC
Edit: I figured out a solution with help from the answers below, thanks all!
SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
ON p.product_id=ph.product_id
AND ph.photo_order =
(
SELECT MIN(z.photo_order)
FROM product_photos AS z
WHERE z.product_id=p.product_id
)
GROUP BY p.product_id
ORDER BY p.product_title ASC
See Question&Answers more detail:
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