I'm trying to write an app that works in system tray using PyQt5.
The code is sometimes raising exceptions, and I need to be able to catch them.
I would expect that when an exception occurs in an app, the main event loop is exited, so catching it like that should work:
try:
application.exec()
except:
do_stuff()
In the following example, when I press the "Raise" button, I only see the traceback, but I never see the error catched!
printed.
from PyQt5 import QtWidgets, QtGui, QtCore
class ErrorApp():
def __init__(self):
# Init QApplication, QWidet and QMenu
self.app = QtWidgets.QApplication([])
self.widget = QtWidgets.QWidget()
self.menu = QtWidgets.QMenu("menu", self.widget)
# Add items to menu
self.menu_action_raise = self.menu.addAction("Raise")
self.menu_action_raise.triggered.connect(self.raise_error)
self.menu_action_exit = self.menu.addAction("Exit")
self.menu_action_exit.triggered.connect(self.app.exit)
# Create the tray app
self.tray = QtWidgets.QSystemTrayIcon(QtGui.QIcon("logo.png"), self.widget)
self.tray.setContextMenu(self.menu)
# Show app
self.tray.show()
def raise_error(self):
assert False
e = ErrorApp()
try:
e.app.exec()
except:
print("error catched!")
There are 2 similar questions, but the answers there don't do what I need to do:
Grab any exception in PyQt: the OP wants to monitor the exceptions, the even loop isn't exited
Preventing PyQt to silence exceptions occurring in slots: the decorator answer simply doesn't work; adding sys.exit(1)
to sys.excepthook
just closes the whole program, without printing error catched!
See Question&Answers more detail:
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