I am now trying to figure out how I can recover a numpy array from base64 data. This question and answer suggest it is possible: Reading numpy arrays outside of Python but an example is not given.
Using the code below as an example, how can I get a Numpy array from the base64 data if I know the dtype and the shape of the array?
import base64
import numpy as np
t = np.arange(25, dtype=np.float64)
s = base64.b64encode(t)
r = base64.decodestring(s)
q = ?????
I want a python statement to set q as a numpy array of dtype float64 so the result is an array identical to t. This is what the arrays encoded and decoded look like:
>>> t = np.arange(25,dtype=np.float64)
>>> t
array([ 0., 1., 2., 3., 4., 5., 6., 7., 8., 9., 10.,
11., 12., 13., 14., 15., 16., 17., 18., 19., 20., 21.,
22., 23., 24.])
>>> s=base64.b64encode(t)
>>> s
'AAAAAAAAAAAAAAAAAADwPwAAAAAAAABAAAAAAAAACEAAAAAAAAAQQAAAAAAAABRAAAAAAAAAGEAAAAAAAAAcQAAAAAAAACBAAAAAAAAAIkAAAAAAAAAkQAAAAAAAACZAAAAAAAAAKEAAAAAAAAAqQAAAAAAAACxAAAAAAAAALkAAAAAAAAAwQAAAAAAAADFAAAAAAAAAMkAAAAAAAAAzQAAAAAAAADRAAAAAAAAANUAAAAAAAAA2QAAAAAAAADdAAAAAAAAAOEA='
>>> r = base64.decodestring(s)
>>> r
'x00x00x00x00x00x00x00x00x00x00x00x00x00x00xf0?x00x00x00x00x00x00x00@x00x00x00x00x00x00x08@x00x00x00x00x00x00x10@x00x00x00x00x00x00x14@x00x00x00x00x00x00x18@x00x00x00x00x00x00x1c@x00x00x00x00x00x00 @x00x00x00x00x00x00"@x00x00x00x00x00x00$@x00x00x00x00x00x00&@x00x00x00x00x00x00(@x00x00x00x00x00x00*@x00x00x00x00x00x00,@x00x00x00x00x00x00.@x00x00x00x00x00x000@x00x00x00x00x00x001@x00x00x00x00x00x002@x00x00x00x00x00x003@x00x00x00x00x00x004@x00x00x00x00x00x005@x00x00x00x00x00x006@x00x00x00x00x00x007@x00x00x00x00x00x008@'
>>> q = np.array( ????
The reason I am asking is because I am working on a project where I would like to store a lot of Numpy arrays in a MySQL database in an app powered by django.
Using this django snippet I can store base64 data in a textfield: http://djangosnippets.org/snippets/1669/
I want to write the arrays to the database as base64 instead of converting the arrays to a string of unicode.
Thanks for your help.
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